(b+2)(-b^2+4b-3)=0

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Solution for (b+2)(-b^2+4b-3)=0 equation:


Simplifying
(b + 2)(-1b2 + 4b + -3) = 0

Reorder the terms:
(2 + b)(-1b2 + 4b + -3) = 0

Reorder the terms:
(2 + b)(-3 + 4b + -1b2) = 0

Multiply (2 + b) * (-3 + 4b + -1b2)
(2(-3 + 4b + -1b2) + b(-3 + 4b + -1b2)) = 0
((-3 * 2 + 4b * 2 + -1b2 * 2) + b(-3 + 4b + -1b2)) = 0
((-6 + 8b + -2b2) + b(-3 + 4b + -1b2)) = 0
(-6 + 8b + -2b2 + (-3 * b + 4b * b + -1b2 * b)) = 0
(-6 + 8b + -2b2 + (-3b + 4b2 + -1b3)) = 0

Reorder the terms:
(-6 + 8b + -3b + -2b2 + 4b2 + -1b3) = 0

Combine like terms: 8b + -3b = 5b
(-6 + 5b + -2b2 + 4b2 + -1b3) = 0

Combine like terms: -2b2 + 4b2 = 2b2
(-6 + 5b + 2b2 + -1b3) = 0

Solving
-6 + 5b + 2b2 + -1b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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